Does the bullet resist the barrel going backward or does the barrel resist the bullet going forward? Both! In equal proportions. Friction force acts on both things equally. Rifling, smoothbore, bullet diameter doesn’t matter because while the forces may vary they always act equally.
Correct, here's the rub.
The forces are analyzed relative to each one of the bodies in motion. Force is a vector with a direction and a magnitude, and a body to which it applies. So, the force vector for the friction on the bullet is a relatively short vector pointing toward the chooter. By the time the slide moves, the bullet is gone, so the friction vector inside the barrel is gone as well.
Well...A key part, but other factors are in play. A lighter bullet can cause a slide to cycle faster in recoil.
Yes, and already noted.
That's why it's called "Short" recoil operated.
Nope. If the slide waits for the bullet to exit before it moves, it won't move. This was the basis for calling out Kuhnhausen for his "Balanced Thrust Vector" description of operation.
The majority of felt recoil comes from the compression of the spring. In this video, you'll notice not only a distinct lack of muzzle flip, but also a slower movement of the pistol overall.
First my qualifying statement. I’m not a physicist.
Due to its mass, and outside forces acting on it, the slide actually presents the greater resistance. That's why the bullet outruns it.
Correct. But in his hypothetical scenario, he said that the barrel can handle the pressure and is completely sealed. And at the time of pulling the trigger the bullet stuck almost immediately. I understood that to mean no gasses could escape through the barrel. But since the slide was not impeded from movement, would the forces push the slide rearward? Letting the gasses/energy escape?
Correct. I understand it if the barrel is not obstructed like in his scenario. He said that if the barrel were sealed and the bullet stopped almost immediately the slide would not move either. This is what I’m asking about.
In a locked breech arm, if the bullet is completely impeded...stopped...by the barrel, the slide IS impeded. In order for the slide to move backward, the barrel has to be able to move backward. Stop any and all backward barrel movement, and the slide can't move.
Thats a closed system, so all forces are acting equally in all directions.
Cool thank you.
Yes., but due to its mass and outside forces, it would still present a greater resistance in normal operation. Block all bullet movement, and the slide is the path of least resistance.
Ok thank you for the explanations.
I edited and added to my last response. I forgot we were addressing a blocked bullet hypothetical.
Right, that's when the slide acquires a force vector that will make it move. Prior to that, the force vector is on the brass, making it move.
I'd be more apt to describe it as a controlled explosion. A contained explosion is essentially a closed bomb test.
Walther CCP as well.
You are trying to grasp the concept of inertia. Physical laws AWAYS apply. Sum of forces at any point are a
Wasn’t this the gun nobody liked?
Only a small part of the felt recoil comes from slide to frame impact. The rest comes from the compressing spring. Since straight/unlocked blowback actions tend to need/have stiffer springs, their recoil is sharper.
Yes. Had one, hated it