Can you think before you calculate?

I’d really love to mess with their heads but it probably wouldn’t be that funny to them ...

A: can’t be calculated ... there is no bend radius given for the cable in question and there is at least one point of bend in the problem
B: 10 meters above the ground is impossible because even with the pole together no cable has a bend radius of ZERO
 
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Isn't that negative acceleration? Been awhile since my last physics class, though.

ahhh... I don’t remember either....
But would it still count if you do not act upon the accelerator force (ie braking) but just stop the acceleration and let gravity and friction do their thing?
 
This one really sucks

183B3928-FEF8-4D68-AA77-B2A82D74AAB0.jpeg

Trying to figure how much each person can do in an hour:

Alice/Bob can do 50% of the job in an hour.

Alice/Charlie can do 33.33% of the job in an hour.

Bob/Charlie can do 25% of the job in an hour.


Working on it...
 
Trying to figure how much each person can do in an hour:

Alice/Bob can do 50% of the job in an hour.

Alice/Charlie can do 33.33% of the job in an hour.

Bob/Charlie can do 25% of the job in an hour.


Working on it...
The correct answer is 3 sum.
 
Trying to figure how much each person can do in an hour:

Alice/Bob can do 50% of the job in an hour.

Alice/Charlie can do 33.33% of the job in an hour.

Bob/Charlie can do 25% of the job in an hour.


Working on it...
Hint: define the job as "load 1200 rounds of 9mm".
 
Hint: define the job as "load 1200 rounds of 9mm".

Alright....

Alice/Bob = 600 rounds / hour
Alice/Charlie = 400 rounds / hour
Bob /Charlie = 300 rounds / hour

So, the three of them working together should be able to load 1300 rounds in one hour.

Right so far?
 
Alright....

Alice/Bob = 600 rounds / hour
Alice/Charlie = 400 rounds / hour
Bob /Charlie = 300 rounds / hour

So, the three of them working together should be able to load 1300 rounds in one hour.

Right so far?
You're getting there, but recheck your math. If Alice+Bob= 600 rounds per hour, adding Charlie is not going to double the output.
 
You're getting there, but recheck your math. If Alice+Bob= 600 rounds per hour, adding Charlie is not going to double the output.

Gotcha...was running all the numbers in my head while I was burning a cancer stick and the numbers weren’t jiving.
 
I agree with your assessment, but this is like one of those math problems-
Man A is driving at 60 miles per hour for 3 hours, he stops for lunch for one hour, then continues to travel at 60 miles per hour for 2 more hours.... How far....
They never take into consideration acceleration and deceleration. Their version of events requires instant locomotion, which violates all sorts of Newtonian Physics....
Man A is dead, very dead.
 
I’m going to go mow my yard, think about this some more and see if I can get it figured out...

Starting to feel like Tommy in Shawshank Redemption...lol.
 
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Assuming they are not looking for their applicants to understand 2nd year calculus of hanging cables, I’d simplify the problem to triangles and solve it pythagorean style. Half the cable is 40 m. The pole minus the distance from the ground is 30m. So, Half the distance between the poles is SQRT(40^2 -30^2)=SQRT(70)=8.37m. So the poles are 16.74m apart, more or less.

I am bad at math, but i really don't remember what the scottish terrier symbol stands for? is that a constant?
 
Dont listen to me i math real bad today

^2 means "squared" tho
 
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I think it is so funny that we have throw back intellectual questions from the MIT days for Interview questions.

I won't name the company, but I had to select one of these type of questions to offset our behavioral questions especially when the opportunity required solid analytical gifts. We never looked for the right answer; but more for honesty.

1. Brain-iac type candidate would answer it perfectly like Newton...

2. Most candidates would try, get it wrong.. you would explain and that is where you could see if they recall and help along the way.

3. For me, the best answer... especially since the question was from Amazon.... was always something like, "Well.. dang...How is that going to help you sell more frickin hammers?"

3rd type was always moved to top of the list.
 
Alice/Bob = 1/2 the job in 1 hour
Alice / Charlie = 1/3 the job in 1 hour
Bob /Charlie = 1/4 the job in 1 hour

If the three of them work together, Bob represents 1/3 the total, so take Bob out of the above 3 combinations...

Alice = 1/2 minus Bob
Charlie = 1/4 minus Bob

So [1/2 (Alice) - Bob + 1/4 (Charlie) - Bob] has to equal 1/3. LCM of 2, 4 and 3 is 12...

6/12 (Alice) + 3/12 (Charlie) = 9/12
9/12 - 4/12 (Bob’s 1/3 of the trio) = 5/12, so Bob, who we took outta the picture twice, is 5/24. Now we can figure out Alice and Charlie.

Alice: 1/2 minus 5/24. LCM 24. 12/24 - 5/24 = 7/24

Charlie: 1/4 minus 5/24. LCM 24. 6/24 - 5/24 1/24

In one hour, Alice (7/24) + Charlie (1/24) + Bob ( 5/24) = 13/24

If my math is right, I’m coming up with between 110-111 minutes for the 3 of them to finish the job.

@Pack72 ...

Sound right?
 
If this were Tortuga, we could speculate on the why of the time differences...

[emoji23][emoji23]

Sent from my Pixel 2 using Tapatalk
 
Alright....

Alice/Bob = 600 rounds / hour
Alice/Charlie = 400 rounds / hour
Bob /Charlie = 300 rounds / hour

Right so far?
Alice+Charlie= 400.

(Alice+Bob) +(Bob+Charlie) = 600+300 = 900
Alice+ (2×Bob) +Charlie = 900
Subtract Alice+Charlie, or 400, from each side of the equation
(2×Bob)=900-400=500.
Bob=250 rounds per hour.
Alice+Bob=600, so Alice=350.
Alice+Charlie=400, so Charlie=50.
Then the total rounds per hour = 350+250+50, or 650.
And the time is 1200/650 hours. Or about 111 minutes.
 
Alice/Bob = 1/2 the job in 1 hour
Alice / Charlie = 1/3 the job in 1 hour
Bob /Charlie = 1/4 the job in 1 hour

If the three of them work together, Bob represents 1/3 the total, so take Bob out of the above 3 combinations...

Alice = 1/2 minus Bob
Charlie = 1/4 minus Bob

So [1/2 (Alice) - Bob + 1/4 (Charlie) - Bob] has to equal 1/3. LCM of 2, 4 and 3 is 12...

6/12 (Alice) + 3/12 (Charlie) = 9/12
9/12 - 4/12 (Bob’s 1/3 of the trio) = 5/12, so Bob, who we took outta the picture twice, is 5/24. Now we can figure out Alice and Charlie.

Alice: 1/2 minus 5/24. LCM 24. 12/24 - 5/24 = 7/24

Charlie: 1/4 minus 5/24. LCM 24. 6/24 - 5/24 1/24

In one hour, Alice (7/24) + Charlie (1/24) + Bob ( 5/24) = 13/24

If my math is right, I’m coming up with between 110-111 minutes for the 3 of them to finish the job.

@Pack72 ...

Sound right?
Yes.
 
Some of y’all probably need to watch this again... :D


She’s the full both dishwasher cups with Dawn ultra type. I’m SOOOOO GLAD I didn’t hitch my wagon for life to a dame bread chick!
The amazing part is I was a going no where stoner at the time.
 
Alright....

Alice/Bob = 600 rounds / hour
Alice/Charlie = 400 rounds / hour
Bob /Charlie = 300 rounds / hour

So, the three of them working together should be able to load 1300 rounds in one hour.

Right so far?

No, but the first 3 lines make it trivial.
Bob is 200/hr faster than Charlie from lines 1 and 2.
Bob is 250, Charlie is 50, from line 3
Therefore Alice is 350.
Rate for all 3=650
1100/650 =hours for all 3 to finish.
 
No, but the first 3 lines make it trivial.
Bob is 200/hr faster than Charlie from lines 1 and 2.
Bob is 250, Charlie is 50, from line 3
Therefore Alice is 350.
Rate for all 3=650
1100/650 =hours for all 3 to finish.

All things being equal... you are correct.

Looking at it from an Organizational Behavior standpoint... Charlie is a ho...

Alice may be faster than Bob but both are faster than when they work with Charlie... so why are they so low with Charlie?

Some boot knockin and shennanigans are going on wherever Charlie is working and they ain't loading bullets the way they should be!
 
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