Dana 60

[SimpleMan]

Gentleman, I am in the process of replacing the rotors, pads, calipers, wheel bearings, grease seals and manual hubs on the front axle of my sons (well now mine since he's stepping up and buying his own/newer ride) 1996 Ford F250. It's a Dana 60 (3850 lb I believe). My question is does anyone know the proper torque for the spindle nuts? I took them off with a screwdriver which was a bit unnerving. I have the proper socket and torque wrench to reassemble.

What I've seen so far on the internet is seat the inner to 50 lbs and then back off 90 degrees, install the lock ring (has a tab that has to be lined up with spindle and a small pin on inner nut lines up with hole in ring). Then apply 160 to 200 lbs to outer nut.

I would like to verify this with anyone that would know for sure, thanks in advance.

 

[Beef15]

If you don't get a response I can Alldata that for you tomorrow, might need to PM then me cause I'm forgetful.
Never used it, AutoZone has repair guides online, might be something there.
That said what you found looks pretty standard.
I personally have never been a fan of backing off X degrees, usually results in very loose, if so I prefer to back off and bring up finger tight.
Tips: Torque the inner while rotating the hub, try flipping the lock ring if it doesn't line up, always tighter never loser to align if that doesn't work. Check end play once you get everything set and also make sure the hub turns pretty free.

 

[SimpleMan]

@Beef15 Thanks for the input. Gonna put it back together tonight. I called a guy I know that works on big trucks and dump trucks. Your info and his coincides down to tightening inner nut to line up ring if needed. I appreciate it!